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Problem 935

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  1. vf_b5b22b3c5278e0ff

    theoretical

    Erdős Problem #935: declared status 'open'. Formalized: no. For any integer n=pkpn=\prod p^{k_p} let Q2(n)Q_2(n) be the powerful part of nn, so thatQ2(n)=pkp2pkp.Q_2(n) = \prod_{\substack{p\\ k_p\geq 2}}p^{k_p}.Is it true that, for every ϵ>0\epsilon>0 and 1\ell\geq 1, if nn is sufficiently large thenQ2(n(n+1)(n+))<n2+ϵ?Q_2(n(n+1)\cdots(n+\ell))<n^{2+\epsilon}?If 2\ell\geq 2 then islim supnQ2(n(n+1)(n+))n2\limsup_{n\to \infty}\frac{Q_2(n(n+1)\cdots(n+\ell))}{n^2}infinite? If 2\ell\geq 2 then islimnQ2(n(n+1)(n+))n+1=0?\lim_{n\to \infty}\frac{Q_2(n(n+1)\cdots(n+\ell))}{n^{\ell+1}}=0? Current best: A result of Mahler implies, for every 1\ell\geq 1,lim supnQ2(n(n+1)(n+))n21.\limsup_{n\to \infty}\frac{Q_2(n(n+1)\cdots(n+\ell))}{n^2}\geq 1.All these questions can be asked replacing Q2Q_2 by QrQ_r for r>2r>2, only keeping those prime powers with exponent r\geq r. Prize: no. OEIS: A057521, A389244. Tags: number theory.

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