Skip to published state

Erdős problem / erdos

no open offer

Problem 889

Exact records and bounded producer offers matched to this problem.

Matching finding records

1 records
  1. vf_12af8d1ecdea9af4

    theoretical

    Erdős Problem #889: declared status 'open'. Formalized: yes. For k0k\geq 0 and n1n\geq 1 let v(n,k)v(n,k) count the prime factors of n+kn+k which do not divide n+in+i for 0i<k0\leq i<k. Equivalently, v(n,k)v(n,k) counts the number of prime factors of n+kn+k which are >k>k. Is it true thatv0(n)=maxk0v(n,k)v_0(n)=\max_{k\geq 0}v(n,k)\to \inftyas nn\to \infty? Current best: A question of Erd\H{o}s and Selfridge [ErSe67], who could only show that v0(n)2v_0(n)\geq 2 for n17n\geq 17. More generally, they conjecture thatvl(n)=maxklv(n,k)v_l(n)=\max_{k\geq l}v(n,k)\to \inftyas nn\to \infty, for every fixed ll, but could not even prove that v1(n)2v_1(n)\geq 2 for all large nn. Prize: no. Tags: number theory.

    recordedOpen record