Skip to published state

Erdős problem / erdos

no open offer

Problem 793

Exact records and bounded producer offers matched to this problem.

Matching finding records

1 records
  1. vf_d239b02fc4cc6e40

    theoretical

    Erdős Problem #793: declared status 'open'. Formalized: no. Let F(n)F(n) be the maximum possible size of a subset A{1,,n}A\subseteq\{1,\ldots,n\} such that abca\nmid bc whenever a,b,cAa,b,c\in A with aba\neq b and aca\neq c. Is there a constant CC such thatF(n)=π(n)+(C+o(1))n2/3(logn)2?F(n)=\pi(n)+(C+o(1))n^{2/3}(\log n)^{-2}? Current best: Erd\H{o}s [Er38] proved there exist constants 0<c1c20<c_1\leq c_2 such thatπ(n)+c1n2/3(logn)2F(n)π(n)+c2n2/3(logn)2.\pi(n)+c_1n^{2/3}(\log n)^{-2}\leq F(n) \leq \pi(n)+c_2n^{2/3}(\log n)^{-2}.Erd\H{o}s [Er69] gave a simple proof that F(n)π(n)+n2/3F(n) \leq \pi(n)+n^{2/3}: define a graph with vertex set the union of those integers in [1,n2/3][1,n^{2/3}] with all primes p(n2/3,n]p\in (n^{2/3},n]. It is easy to see that every mnm\leq n can be written as uvuv where un2/3u\leq n^{2/3} and vv is either prime or n2/3\leq n^{2/3}, and hence there are A\geq \lvert A\rvert many edges. This can be improved to give the upper bound mentioned by using a subset of integers in [1,n2/3][1,n^{2/3}]. More generally, one can ask for such an asymptotic for the size of sets such that no aAa\in A divides the product of rr distinct other elements of AA, with the exponent 2/32/3 replaced by 2r+1\frac{2}{r+1}. Prize: no. Tags: number theory.

    recordedOpen record