Erdős problem / erdos
no open offerProblem 708
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theoretical
Erdős Problem #708: declared status 'open'. Formalized: no. Let be minimal such that for any with and any set of consecutive integers there exists some with such thatIs it true thatOr perhaps even ? Current best: Their lower bound construction takes as the set of for , where is some set of primes such that . (In 1992 1000 rupees was worth approximately \c_n\geq 1I\subset [0,\infty)c_n\max(A)B\subseteq I\cap \mathbb{N}\lvert B\rvert=n such that\[\prod_{a\in A} a \mid \prod_{b\in B}b.\]They prove c_2=1c_3=\sqrt{2}100. Tags: number theory.
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