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Problem 695

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  1. vf_2913b5b453983036

    theoretical

    Erdős Problem #695: declared status 'open'. Formalized: yes. Let p1<p2<p_1<p_2<\cdots be a sequence of primes such that pi+11(modpi)p_{i+1}\equiv 1\pmod{p_i}. Is it true thatlimkpk1/k=?\lim_k p_k^{1/k}=\infty?Does there exist such a sequence withpkexp(k(logk)1+o(1))?p_k \leq \exp(k(\log k)^{1+o(1)})? Current best: If we take the obvious 'greedy' chain with 2=p12=p_1 and pi+1p_{i+1} is the smallest prime 1(modpi)\equiv 1\pmod{p_i} then Linnik's theorem implies that this sequence grows likepkeeO(k).p_k \leq e^{e^{O(k)}}.It is conjectured that, for any prime pp, there is a prime pp(logp)O(1)p'\leq p(\log p)^{O(1)} which is congruent to 1(modp)1\pmod{p}, which would imply this sequence grows likepkexp(k(logk)1+o(1)).p_k\leq \exp(k(\log k)^{1+o(1)}).An extensive study of the growth of finite prime chains was carried out by Ford, Konyagin, and Luca [FKL10]. Prize: no. OEIS: A061092. Tags: number theory.

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