Erdős problem / erdos
no open offerProblem 665
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theoretical
Erdős Problem #665: declared status 'open'. Formalized: no. Is there some constant such that for every there are such that for all , and for all , and every pair has for some ? Current best: Shrikhande and Singhi [ShSi85] have proved that the answer is no conditional on the conjecture that the order of every projective plane is a prime power (see [723]), by proving that every pairwise balanced design on points in which each block is of size can be embedded in a projective plane of order for some , if is sufficiently large. Prize: no. Tags: combinatorics.
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