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Problem 236

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  1. vf_ea088f13ed98d3c2

    theoretical

    Erdős Problem #236: declared status 'open'. Formalized: yes. Let f(n)f(n) count the number of solutions to n=p+2kn=p+2^k for prime pp and k0k\geq 0. Is it true that f(n)=o(logn)f(n)=o(\log n)? Current best: Mientka and Weitzenkamp [MiWe69] have proved there are no other such n244n\leq 2^{44}. Vaughan [Va73] has proved that the number of nNn\leq N such that n2kn-2^k is prime for all 2k<n2^k<n is<exp(clogloglogNloglogNlogN)N< \exp\left(-c\frac{\log \log \log N}{\log\log N}\log N\right)Nfor some constant c>0c>0. Prize: no. OEIS: A039669, A109925. Tags: number theory, primes.

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