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Problem 106

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  1. vf_8708c4c47db9a04b

    theoretical

    Erdős Problem #106 [status: falsifiable; formalized: no]. Draw nn squares inside the unit square with no common interior point. Let f(n)f(n) be the maximum possible sum of the side-lengths of the squares. Is f(k2+1)=kf(k^2+1)=k? Current best: Hal\'{a}sz [Ha84] gives a construction that shows f(k2+2)k+1k+1f(k^2+2)\geq k+\frac{1}{k+1}, and in general, for any c1c\geq 1,f(k2+2c+1)k+ckf(k^2+2c+1)\geq k+\frac{c}{k}andf(k2+2c)k+ck+1.f(k^2+2c)\geq k+\frac{c}{k+1}.Hal\'{a}sz also considers the variants where we replace a square by a parallelogram or triangle. Erd\H{o}s and Soifer [ErSo95] and Campbell and Staton [CaSt05] have conjectured that, in general, for any integer k<c<k-k<c<k, f(k2+2c+1)=k+ckf(k^2+2c+1)=k+\frac{c}{k}, and proved the corresponding lower bound. Prize: no. Tags: geometry.

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