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Erdős Problem #393

Canonical assertion

declared status 'open'. Formalized: no. Let f(n)f(n) denote the minimal m1m\geq 1 such thatn!=a1atn! = a_1\cdots a_twith a1<<at=a1+ma_1<\cdots <a_t=a_1+m. What is the behaviour of f(n)f(n)? Current best: Let Fm(N)F_m(N) count the number of nNn\leq N such that f(n)=mf(n)=m. Prize: no. OEIS: A388302. Tags: factorials, number theory.

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Provenance summary
erdos_deep:393
database_record
Jun 16, 2026, 12:00 AM
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Exact record identityFinding ID, frontier identity, and pinned Git source
vf_e9f4971af58eef2c
vfr_0a25edabc16db143
ce8ba7d934c848408e0d91caca39e938698e3fc7
03f7371b496485f761f91961027fd48198dc7e93
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ce8ba7d934c848408e0d91caca39e938698e3fc7
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03f7371b496485f761f91961027fd48198dc7e93
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2026-07-20T19:20:20-04:00
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