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vf_14f002b48d251c04

Erdős Problem #371

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declared status 'open'. Formalized: yes. Let P(n)P(n) denote the largest prime factor of nn. Show that the set of nn with P(n)<P(n+1)P(n)<P(n+1) has density 1/21/2. Current best: The best unconditional lower bound available is due to L\"{u} and Wang [LuWa25], who prove that#{n<x:P(n)<P(n+1)}>(0.2017o(1))x,\#\{ n<x :P(n)<P(n+1)\} > (0.2017-o(1))x,and the same lower bound for the complement. Tao and Ter\"{a}v\"{a}inen [TaTe19] have proved that the asymptotic density is 1/21/2 at 'almost all scales'. More generally, for any 0α10\leq \alpha \leq1, Ter\"{a}v\"{a}inen [Te18] proved that the logarithmic density of the set of nn for which P(n+1)>P(n)nαP(n+1)>P(n)n^\alpha exists and is equal to[0,1]21yx+αu(x)u(y)dxdy\int_{[0,1]^2}1_{y\geq x+\alpha}u(x)u(y)\mathrm{d}x\mathrm{d}ywhere u(x)=x1ρ(x11)u(x)=x^{-1}\rho(x^{-1}-1) and ρ\rho is the Dickman function. Wang [Wa21] has proved the same value holds for the asymptotic density (and in particular provided an affirmative answer to the original question) conditional on the Elliott-Halberstam conjecture for friable integers. Prize: no. OEIS: A070089. Tags: number theory.

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Jun 16, 2026, 12:00 AM
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vf_14f002b48d251c04
vfr_0a25edabc16db143
ce8ba7d934c848408e0d91caca39e938698e3fc7
03f7371b496485f761f91961027fd48198dc7e93
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