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Erdős Problem #959

Canonical assertion

declared status 'open'. Formalized: no. Let AR2A\subset \mathbb{R}^2 be a set of size nn and let {d1,,dk}\{d_1,\ldots,d_k\} be the set of distinct distances determined by AA. Let f(d)f(d) be the number of times the distance dd is determined, and suppose the did_i are ordered such thatf(d1)f(d2)f(dk).f(d_1)\geq f(d_2)\geq \cdots \geq f(d_k).Estimatemax(f(d1)f(d2)),\max (f(d_1)-f(d_2)),where the maximum is taken over all AA of size nn. Current best: More generally, one can ask aboutmax(f(dr)f(dr+1)).\max (f(d_r)-f(d_{r+1})).Clemen, Dumitrescu, and Liu [CDL25], have shown thatmax(f(d1)f(d2))nlogn.\max (f(d_1)-f(d_2))\gg n\log n.More generally, for any 1klogn1\leq k\leq \log n, there exists a set AA of nn points such thatf(dr)f(dr+1)nlognr.f(d_r)-f(d_{r+1})\gg \frac{n\log n}{r}.They conjecture that nlognn\log n can be improved to n1+c/loglognn^{1+c/\log\log n} for some constant c>0c>0. Prize: no. Tags: distances, geometry.

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erdos_deep:959
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Jun 16, 2026, 12:00 AM
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vf_09bf1d3fd8e4e526
vfr_0a25edabc16db143
ce8ba7d934c848408e0d91caca39e938698e3fc7
03f7371b496485f761f91961027fd48198dc7e93
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ce8ba7d934c848408e0d91caca39e938698e3fc7
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2026-07-20T19:20:20-04:00
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